Question

Which of the numbers 4, 5, and 6 is a solution of 3x + 2 ≥ 20

Answer 1

None of the numbers 4, 5, or 6 are solutions of the inequality 3x + 2 ≥ 20.

Let's check each number:

For x = 4, substitute x = 4 into the inequality:
3(4) + 2 ≥ 20
12 + 2 ≥ 20
14 ≥ 20
14 is not greater than or equal to 20, so x = 4 is not a solution.

For x = 5, substitute x = 5 into the inequality:
3(5) + 2 ≥ 20
15 + 2 ≥ 20
17 ≥ 20
17 is not greater than or equal to 20, so x = 5 is not a solution.

For x = 6, substitute x = 6 into the inequality:
3(6) + 2 ≥ 20
18 + 2 ≥ 20
20 ≥ 20
20 is equal to 20, not greater, so x = 6 is not a solution.

Therefore, none of the numbers 4, 5, or 6 are solutions of the inequality 3x + 2 ≥ 20.