Question

Which of the numbers 4, 5, and 6 is a solution of 3x + 2 ≥ 20 ?

Answer 1

Let x = 4, 5, and 6:

For x = 4:
3(4) + 2 ≥ 20
12 + 2 ≥ 20
14 ≥ 20 (False)

For x = 5:
3(5) + 2 ≥ 20
15 + 2 ≥ 20
17 ≥ 20 (False)

For x = 6:
3(6) + 2 ≥ 20
18 + 2 ≥ 20
20 ≥ 20 (True)

Therefore, the number 6 is a solution to the inequality 3x + 2 ≥ 20.