Asked by thalia
a box with mass 20kg rests on a frictionless ramp with a 15degree slope. a mover pulls up on a rope attached to the box to pull it up the incline. if the rope makes a 40 degree angle with the horizontal, what's the smallest force that the mover will have to exert to move the box up the ramp?
Answers
Answered by
bobpursley
Ok, the rope makes a 25 degree pull from the direction of the ramp. That means it has a component in the direction of the ramp (F*cos25)
Weight of the box is directed down the ramp, mgSin15
So F*cos25=mgSin15 to put it in equilibrium, and F has to be slightly larger to move it up the ramp. Solve for F
Weight of the box is directed down the ramp, mgSin15
So F*cos25=mgSin15 to put it in equilibrium, and F has to be slightly larger to move it up the ramp. Solve for F
Answered by
Angjabgkj
Dsgfalkngksndg;jsb
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