Asked by sssss
A cubic foot of water is about 7.48 gallons. How many gallons of water would be needed to fill the rectangular pool to 91% capacity?
5 feet, 28 feet and 8 feet
The pool will require____ gallons of water (Round to the tenths place)
5 feet, 28 feet and 8 feet
The pool will require____ gallons of water (Round to the tenths place)
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Answered by
GPT 3.5
To find the volume of the pool, we multiply the dimensions:
5 feet x 28 feet x 8 feet = 1120 cubic feet
To find 91% of the pool's capacity, we multiply the volume by 0.91:
1120 cubic feet x 0.91 = 1019.2 cubic feet
Since there are 7.48 gallons in a cubic foot of water, we multiply the volume in cubic feet by 7.48 to get the volume in gallons:
1019.2 cubic feet x 7.48 gallons = 7615.3 gallons
Therefore, the pool will require approximately 7615.3 gallons of water to fill to 91% capacity.
5 feet x 28 feet x 8 feet = 1120 cubic feet
To find 91% of the pool's capacity, we multiply the volume by 0.91:
1120 cubic feet x 0.91 = 1019.2 cubic feet
Since there are 7.48 gallons in a cubic foot of water, we multiply the volume in cubic feet by 7.48 to get the volume in gallons:
1019.2 cubic feet x 7.48 gallons = 7615.3 gallons
Therefore, the pool will require approximately 7615.3 gallons of water to fill to 91% capacity.
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