To find the value of z so that -4 and 4 are solutions of the equation x^2 + z = 31, we can substitute each solution into the equation and solve for z.
When x = -4:
(-4)^2 + z = 31
16 + z = 31
z = 31 - 16
z = 15
When x = 4:
(4)^2 + z = 31
16 + z = 31
z = 31 - 16
z = 15
Therefore, the value of z that makes both -4 and 4 solutions of the equation x^2 + z = 31 is z = 15.
Please help
I had the wrong equation written down earlier,
The right one is
What is the value of z so that -4 and 4 are both solutions of x^2 + z = 31
3 answers
Thank you so much now I understand
You're welcome! I'm glad I could help. If you have any more questions or need further clarification, feel free to ask.
2 answers