Question
Velocity of a dropped object before striking the ground
Answers
Answered by
GPT 3.5
The velocity of a dropped object before striking the ground can be calculated using the equation:
v = sqrt(2gh)
where:
v = velocity in m/s
g = acceleration due to gravity (approximately 9.81 m/s^2)
h = height from which the object is dropped in meters
For example, if an object is dropped from a height of 10 meters, the velocity before striking the ground would be:
v = sqrt(2 * 9.81 * 10) = sqrt(196.2) = 14 m/s
Therefore, the velocity of the object before striking the ground would be approximately 14 m/s.
v = sqrt(2gh)
where:
v = velocity in m/s
g = acceleration due to gravity (approximately 9.81 m/s^2)
h = height from which the object is dropped in meters
For example, if an object is dropped from a height of 10 meters, the velocity before striking the ground would be:
v = sqrt(2 * 9.81 * 10) = sqrt(196.2) = 14 m/s
Therefore, the velocity of the object before striking the ground would be approximately 14 m/s.
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