Asked by mo
find limit :
lim (3sin4x / sin3x )
x--> 0
lim (3sin4x / sin3x )
x--> 0
Answers
Answered by
drwls
The limit equals the ratio of the derivatives at x=0. That is called L'Hopital's rule.
Limit (12 cos 4x) / (3 cos x)
@ x=4 = ?
Limit (12 cos 4x) / (3 cos x)
@ x=4 = ?
Answered by
mo
sorry, I don't understand can you explain it, please ?
Answered by
bobpursley
If you do not understand derivatives, then you will have to find the trig equivalent of the multiangle (identies)equivalents, and reduce the fractions.
Answered by
Count Iblis
The limit is of the form:
Lim x--> 0 f(x)/g(x)
where f(0) = g(0) = 0. So we can't take the limits for f and g separately and divide them.
Rewrite the limit as:
Lim x--> 0 [f(x) - 0]/[g(x) - 0] =
Lim x--> 0 [f(x)-f(0)]/[g(x)-g(0)]
Lim x-->0{[f(x)-f(0)]/x}/{[g(x)-g(0)]/x}
The limits of the numerator and denominator are the derivatives at zero. If they both exist and are nonzero then the limit is the ratio of these derivatives.
Lim x--> 0 f(x)/g(x)
where f(0) = g(0) = 0. So we can't take the limits for f and g separately and divide them.
Rewrite the limit as:
Lim x--> 0 [f(x) - 0]/[g(x) - 0] =
Lim x--> 0 [f(x)-f(0)]/[g(x)-g(0)]
Lim x-->0{[f(x)-f(0)]/x}/{[g(x)-g(0)]/x}
The limits of the numerator and denominator are the derivatives at zero. If they both exist and are nonzero then the limit is the ratio of these derivatives.
There are no AI answers yet. The ability to request AI answers is coming soon!