Question

A commercial rubbing alcohol contains 63. g of isopropanol and 0.331 g of sucrose octaacetate in each 77. -mL portion. Calculate the
concentration for each component. Be sure each of your answer entries has the correct number of significant figures.

Part 1 of 2

weight
percent
volume

%

weight

volume

isopropanol


what is the answer please

Answer 1

To calculate the weight percent of isopropanol in the rubbing alcohol, first determine the total weight of the 77 mL portion:

(63 g isopropanol + 0.331 g sucrose octaacetate) / 77 mL = 63.331 g / 77 mL = 0.8213 g/mL

Next, calculate the weight percent of isopropanol:

Weight percent = (63 g isopropanol / 63.331 g) x 100% = 99.1%

So, the weight percent of isopropanol in the rubbing alcohol is 99.1%.

Next, calculate the volume percent of isopropanol:

Volume percent = (63 mL isopropanol / 77 mL) x 100% = 81.8%

So, the volume percent of isopropanol in the rubbing alcohol is 81.8%.