Question

A commercial rubbing alcohol contains 63. g of isopropanol and 0.331 g of sucrose octaacetate in each 77. -mL portion. Calculate the
concentration for each component. Be sure each of your answer entries has the correct number of significant figures.

Part 1 of 2

weight
percent
volume

%

weight

volume

isopropanol


Part 2 of 2

%

weight
volume

sucrose octaacetate

Answer 1

Part 1 of 2:

Isopropanol:
Weight percent = (mass of isopropanol / total mass) * 100
Weight percent = (63 g / 63.331 g) * 100
Weight percent = 99.5%

Volume percent = (volume of isopropanol / total volume) * 100
Volume percent = (63 mL / 77 mL) * 100
Volume percent = 81.8%

Part 2 of 2:

Sucrose octaacetate:
Weight percent = (mass of sucrose octaacetate / total mass) * 100
Weight percent = (0.331 g / 63.331 g) * 100
Weight percent = 0.523%

Volume percent = (volume of sucrose octaacetate / total volume) * 100
Volume percent = (0.331 mL / 77 mL) * 100
Volume percent = 0.430%