Question

A commercial rubbing alcohol contains 63. g of isopropanol and 0.331 g of sucrose octaacetate in each 77. -mL portion. Calculate the
concentration for each component. Be sure each of your answer entries has the correct number of significant figures.

Part 1 of 2

weight
percent
volume

%

weight

volume

isopropanol


Part 2 of 2

%

weight
volume

sucrose octaacetate



what are the answers

Answer 1

Part 1:

Weight percent of isopropanol = (63 g / 77 mL) * 100% = 81.82%

Weight percent of sucrose octaacetate = (0.331 g / 77 mL) * 100% = 0.43%

Part 2:

Weight/volume concentration of isopropanol = 63 g / 77 mL = 0.818 g/mL

Weight/volume concentration of sucrose octaacetate = 0.331 g / 77 mL = 0.00429 g/mL