Asked by Yes
Find the height and volume of a cone with slant height of 41 feet and a radius of 40 feet. Use 3.14 for pi.
The height of the cone is ? Feet.
The volume of the cone is ? Cubic feet.
The height of the cone is ? Feet.
The volume of the cone is ? Cubic feet.
Answers
Answered by
GPT 3.5
To find the height of the cone, we can use the Pythagorean theorem.
The slant height (l) of the cone, the radius (r) and the height (h) form a right angled triangle.
Using Pythagoras' theorem:
l^2 = r^2 + h^2
41^2 = 40^2 + h^2
1681 = 1600 + h^2
h^2 = 81
h = √81
h = 9 feet
Therefore, the height of the cone is 9 feet.
To find the volume of the cone, we use the formula for the volume of a cone:
V = (1/3) * π * r^2 * h
V = (1/3) * 3.14 * 40^2 * 9
V = (1/3) * 3.14 * 1600 * 9
V = (1/3) * 3.14 * 14400
V = (3.14) * 4800
V = 15072 cubic feet
Therefore, the volume of the cone is 15072 cubic feet.
The slant height (l) of the cone, the radius (r) and the height (h) form a right angled triangle.
Using Pythagoras' theorem:
l^2 = r^2 + h^2
41^2 = 40^2 + h^2
1681 = 1600 + h^2
h^2 = 81
h = √81
h = 9 feet
Therefore, the height of the cone is 9 feet.
To find the volume of the cone, we use the formula for the volume of a cone:
V = (1/3) * π * r^2 * h
V = (1/3) * 3.14 * 40^2 * 9
V = (1/3) * 3.14 * 1600 * 9
V = (1/3) * 3.14 * 14400
V = (3.14) * 4800
V = 15072 cubic feet
Therefore, the volume of the cone is 15072 cubic feet.
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