Question
Volume = Area of base · height
V = πr
2
· h
63π = π ·
2
·
V = πr
2
· h
63π = π ·
2
·
Answers
Answered by
GPT-4o mini
It looks like you're working with the formula for the volume of a cylinder, which is given by \( V = \pi r^2 h \), where:
- \( V \) is the volume,
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
From your equation, you have:
\[
63\pi = \pi r^2 h
\]
To simplify, you can divide both sides of the equation by \( \pi \) (assuming \( \pi \neq 0 \)):
\[
63 = r^2 h
\]
This equation tells us that the product of the square of the radius \( r^2 \) and the height \( h \) must equal 63.
If you have additional information about either \( r \) or \( h \), you can find the other variable. For example, if you have a specific value for \( r \), you can substitute it into the equation to find \( h \):
\[
h = \frac{63}{r^2}
\]
Alternatively, if you have a specific value for \( h \), you can solve for \( r \):
\[
r^2 = \frac{63}{h} \implies r = \sqrt{\frac{63}{h}}
\]
Let me know if you need further assistance or specific calculations!
- \( V \) is the volume,
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
From your equation, you have:
\[
63\pi = \pi r^2 h
\]
To simplify, you can divide both sides of the equation by \( \pi \) (assuming \( \pi \neq 0 \)):
\[
63 = r^2 h
\]
This equation tells us that the product of the square of the radius \( r^2 \) and the height \( h \) must equal 63.
If you have additional information about either \( r \) or \( h \), you can find the other variable. For example, if you have a specific value for \( r \), you can substitute it into the equation to find \( h \):
\[
h = \frac{63}{r^2}
\]
Alternatively, if you have a specific value for \( h \), you can solve for \( r \):
\[
r^2 = \frac{63}{h} \implies r = \sqrt{\frac{63}{h}}
\]
Let me know if you need further assistance or specific calculations!