Asked by Tommy
Sorry new here trying to figure out angular problem with a disc, only have 2 attempts remaining please help me out :D.
When the play button is pressed, a CD accelerates uniformly from rest to 470rev/min in 3.0 revolutions.
If the CD has a radius of 6.0 cm and a mass of 15 g , what is the torque exerted on it?
When the play button is pressed, a CD accelerates uniformly from rest to 470rev/min in 3.0 revolutions.
If the CD has a radius of 6.0 cm and a mass of 15 g , what is the torque exerted on it?
Answers
Answered by
bobpursley
a Disk? I= 1/2 mr^2
Torque= I*alpha
but alpha= (wf-wi)/time
and time is angular displacement/velocityavg
time= 2PI*3/(1/2 479*2PI/60)
then alpha= 470*2PI/60 / time
do that, then calculate
torque= 1/2 mr^2 * alpha
keep units in mks.
Torque= I*alpha
but alpha= (wf-wi)/time
and time is angular displacement/velocityavg
time= 2PI*3/(1/2 479*2PI/60)
then alpha= 470*2PI/60 / time
do that, then calculate
torque= 1/2 mr^2 * alpha
keep units in mks.
Answered by
Tommy
First person who ever explained something to me that detailed thank you!
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