Question

Sorry I've tried 3 different ways to answer this and all have been wrong, please help me out!

The moment of inertia of a 1.1 kg bicycle wheel rotating about its center is 0.15 kg*m^2

What is the radius of this wheel, assuming the weight of the spokes can be ignored?

Answer 1

I would model the wheel as a hoop>


Mr^2=.15
r= sqrt (.15/1.1)= 37 cm

Answer 2

It would be nice if you posted your three ways to calculate the quantity, and the values that you obtained.

Moment of inertia
=Σmr²
In this case, the weight is all distributed at the rim, ignoring spokes, so
1.1 kg r²=0.15 kg-m²
Solve for r.

Answer 3

Thank you so much guys!!!

Answer 4

You're welcome, Sally!