Question

Foil and Simply (x+1) (x+1)

Answer 1

show me the steps to the answer

Answer 2

First, let's expand the given expression by using the FOIL method, which stands for First, Outer, Inner, Last:

(x+1)(x+1)
= x*x + x*1 + 1*x + 1*1
= x^2 + x + x + 1
= x^2 + 2x + 1

Therefore, the expanded form of (x+1)(x+1) is x^2 + 2x + 1.

Alternatively, we can also simplify the expression:

(x+1)(x+1)
= x^2 + x + x + 1
= x^2 + 2x + 1

So, both the expanded and simplified forms yield the same result: x^2 + 2x + 1.

Answer 3

To expand the expression (x+1)(x+1) using the FOIL method, follow these steps:

1. First: Multiply the first terms in each parenthesis
(x + 1)(x + 1) equals x*x = x^2

2. Outer: Multiply the outer terms in each parenthesis
(x + 1)(x + 1) equals x*1 = x

3. Inner: Multiply the inner terms in each parenthesis
(x + 1)(x + 1) equals 1*x = x

4. Last: Multiply the last terms in each parenthesis
(x + 1)(x + 1) equals 1*1 = 1

5. Combine the results from steps 1 to 4 to get the final expanded form
(x + 1)(x + 1) = x^2 + x + x + 1
= x^2 + 2x + 1

Therefore, the expanded form of (x+1)(x+1) is x^2 + 2x + 1.