Question

01234 h(t) 35742 The table denotes the height reached by a basketball , in feet, t seconds after being thrown . Calculate the rate of change in the basketball's height between the first and fourth secondpoint)

Answer 1

To calculate the rate of change in the basketball's height between the first and fourth second, we need to find the difference in height between the two time points and divide it by the difference in time.

Height at t=1 second: h(1) = 3 feet
Height at t=4 seconds: h(4) = 2 feet

The rate of change in height between the first and fourth second is:

Rate of change = (h(4) - h(1)) / (4 - 1)
Rate of change = (2 - 3) / 3
Rate of change = -1 / 3 = -0.33 feet per second

Therefore, the rate of change in the basketball's height between the first and fourth second is -0.33 feet per second.