Question

Smallest numbers last
-0.0123456...
square root of 15
0
7/3
square root of -45
3 square root of 27

Answer 1

To arrange the given numbers from smallest to largest, we first need to evaluate each one:

1. **-0.0123456...**: This is a negative decimal value.
2. **Square root of 15**: \(\sqrt{15} \approx 3.87\).
3. **0**: This is a neutral value.
4. **7/3**: This value is approximately \(2.33\).
5. **Square root of -45**: This is an imaginary number, specifically \( 3i \sqrt{5} \), since the square root of a negative number is not a real number.
6. **3 square root of 27**: This can be simplified to \(3 \times \sqrt{27} = 3 \times 3\sqrt{3} = 9\sqrt{3} \approx 15.588\).

Now we can arrange the real numbers:

- **-0.0123456...** (the smallest value)
- **Square root of -45** (this is not a real number)
- **0**
- **7/3** (approximately \(2.33\))
- **Square root of 15** (approximately \(3.87\))
- **3 square root of 27** (approximately \(15.588\))

Thus, only considering the real numbers, we have:

**Final arrangement (smallest to largest):**
- -0.0123456...
- 0
- 7/3
- Square root of 15
- 3 square root of 27

The imaginary number (square root of -45) does not have a place in this order among the real numbers.