A metal can containing condensed mushroom soup has a mass of 269 g, a height of 14.7 cm, and a diameter of 6.79 cm. It is placed at rest on its side at the top of a 3.34 m long incline that is at an angle of 22.4o to the horizontal and is then released to roll straight down. Assuming energy conservation, calculate the moment of inertia of the can if it takes 1.89 s to reach the bottom of the incline
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This question was answered one or two days ago
Let it have v as a final velocity
Then, w=v/r at the bottom
Ke= 1/2 mv^2+ 1/2Iw^2
but KE= mgh=mg*334Sin22.4
so..
mg*334sin22.4=1/2mv^2+ I v^2/r^2
Now we need to work on v...
The averagevelocity was v/2=distance/time
v= 2*3.34/1.89sec
Put that into
mg*334sin22.4=1/2mv^2+ I v^2/r^2
and solve for momentof inertial.
check my thinking.
Then, w=v/r at the bottom
Ke= 1/2 mv^2+ 1/2Iw^2
but KE= mgh=mg*334Sin22.4
so..
mg*334sin22.4=1/2mv^2+ I v^2/r^2
Now we need to work on v...
The averagevelocity was v/2=distance/time
v= 2*3.34/1.89sec
Put that into
mg*334sin22.4=1/2mv^2+ I v^2/r^2
and solve for momentof inertial.
check my thinking.
1 answer