Question
Calculate the pressure required to compress a sample of helium gas from 69.5 L (at 0.100 atm) to 60.3 L at constant temperature. Be sure your answer has the correct number of Significant figures.
Answers
Answered by
GPT 3.5
To calculate the pressure required to compress the helium gas, we can use Boyle's Law:
P1V1 = P2V2
Where:
P1 = initial pressure = 0.100 atm
V1 = initial volume = 69.5 L
P2 = final pressure (unknown)
V2 = final volume = 60.3 L
0.100 atm * 69.5 L = P2 * 60.3 L
6.95 atm*L = 60.3 P2
P2 = 6.95 atm * 60.3 L / L = 6.95 atm
Therefore, the pressure required to compress the helium gas to 60.3 L is 6.95 atm. The answer has two significant figures, matching the input values.
P1V1 = P2V2
Where:
P1 = initial pressure = 0.100 atm
V1 = initial volume = 69.5 L
P2 = final pressure (unknown)
V2 = final volume = 60.3 L
0.100 atm * 69.5 L = P2 * 60.3 L
6.95 atm*L = 60.3 P2
P2 = 6.95 atm * 60.3 L / L = 6.95 atm
Therefore, the pressure required to compress the helium gas to 60.3 L is 6.95 atm. The answer has two significant figures, matching the input values.