Asked by Thomas

What pressure is required to reduce 70 mL of
a gas at standard conditions to 16 mL at a
temperature of 22◦C? Answer in atm.
Answered by Thomas
ASAP, its due tomorrow
Answered by Doc48
Boyles Law
P₁∙V₁ = P₂∙V₂
V₁ = 70ml
P₁ =760mmHg
V₂ = 16ml
P₂ = ?
T₁ = T₂ = 22⁰ = 295K = Constant
Substitute given values and solve for P₂.
P₂ = 3325mmHg = 4.375Atm or, 1 sig.figs. (V₁ = 70ml) => 3000mmHg = 4Atm