the temp of air in a foundry increases when molten metals cool and solidify. Suppose a 45 x 10^6 J of energy is added to the surrounding air by the solidifying metal. The air's temp increases by 55 °C, and the air has a specific heat capacity of 1.0 x 10^3 J/kg x °C. What is the mass of the heated air?

User Icon for hgfhf hgfhf answered
10 years ago

54

User Icon for ,m ,m answered
1 year ago

c

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

To find the mass of the heated air, we can use the equation:

Q = mcΔT

Where:
Q = energy added to the air (45 x 10^6 J)
m = mass of the air (unknown)
c = specific heat capacity of air (1.0 x 10^3 J/kg x °C)
ΔT = change in temperature (55 °C)

Rearranging the equation, we get:

m = Q / (c * ΔT)

Substituting the values given:

m = (45 x 10^6 J) / (1.0 x 10^3 J/kg x °C * 55 °C)

Simplifying:

m = (45 x 10^6) / (1.0 x 10^3 * 55)
m = 818.18 kg

Therefore, the mass of the heated air is approximately 818.18 kg.

User Icon for Explain Bot Explain Bot answered
11 months ago

To calculate the mass of the heated air, we can use the formula:

Q = mcΔT

Where:
Q is the amount of energy transferred to the air (45 x 10^6 J)
m is the mass of the air
c is the specific heat capacity of the air (1.0 x 10^3 J/kg x °C)
ΔT is the change in temperature of the air (55 °C).

Rearranging the formula to solve for mass (m), we have:

m = Q / (c * ΔT)

Substituting the given values, we get:

m = 45 x 10^6 J / (1.0 x 10^3 J/kg x °C * 55 °C)

Simplifying the equation further:

m = 45 x 10^6 J / (55 x 10^3 J/kg)

Canceling out the common unit of energy (J) leaves us with:

m = 45 x 10^6 / 55 x 10^3 kg

Calculating:

m = (45 / 55) x (10^6 / 10^3) kg

m = 0.82 x 10^3 kg

So, the mass of the heated air is approximately 820 kg.