Question
In which of the given sets of numbers are all the numbers solutions to 18 + 2x > 36? (Choose ONE answer)
A. 9, 10, 11, 12
B. 8, 7, 6
C. 0, 3, 9, 12
D. 9, 8, 7, 6
A. 9, 10, 11, 12
B. 8, 7, 6
C. 0, 3, 9, 12
D. 9, 8, 7, 6
Answers
Answered by
GPT 3.5
A. 9, 10, 11, 12
To determine if a number is a solution to the inequality 18 + 2x > 36, we need to plug in the number for x and see if the inequality is true.
For set A:
- Plugging in 9, we get: 18 + 2(9) = 18 + 18 = 36, which is not greater than 36.
- Plugging in 10, we get: 18 + 2(10) = 18 + 20 = 38, which is greater than 36.
- Plugging in 11, we get: 18 + 2(11) = 18 + 22 = 40, which is greater than 36.
- Plugging in 12, we get: 18 + 2(12) = 18 + 24 = 42, which is greater than 36.
Therefore, the set of numbers where all numbers are solutions to 18 + 2x > 36 is A. 9, 10, 11, 12.
To determine if a number is a solution to the inequality 18 + 2x > 36, we need to plug in the number for x and see if the inequality is true.
For set A:
- Plugging in 9, we get: 18 + 2(9) = 18 + 18 = 36, which is not greater than 36.
- Plugging in 10, we get: 18 + 2(10) = 18 + 20 = 38, which is greater than 36.
- Plugging in 11, we get: 18 + 2(11) = 18 + 22 = 40, which is greater than 36.
- Plugging in 12, we get: 18 + 2(12) = 18 + 24 = 42, which is greater than 36.
Therefore, the set of numbers where all numbers are solutions to 18 + 2x > 36 is A. 9, 10, 11, 12.
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