Question

In which of the given sets of numbers are all the numbers solutions of
18 + 2x ≥ 36? (1 point)
O 8, 7,6
О 9,8, 7,6
O 9, 10, 11, 12
О 0,3, 9,12

Answer 1

The correct set of numbers where all the numbers are solutions of 18 + 2x ≥ 36 is:

O 9, 10, 11, 12

Because if you plug in each of those values into the inequality:

For x = 9: 18 + 2(9) = 18 + 18 = 36 ≥ 36 (True)
For x = 10: 18 + 2(10) = 18 + 20 = 38 ≥ 36 (True)
For x = 11: 18 + 2(11) = 18 + 22 = 40 ≥ 36 (True)
For x = 12: 18 + 2(12) = 18 + 24 = 42 ≥ 36 (True)

So, all the numbers in the set O 9, 10, 11, 12 satisfy the inequality 18 + 2x ≥ 36.