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Martha has a soup can in the shape of a cylinder with a height of 11 cm and radius of 4 cm. What is the surface area of the can...Asked by your mom
Martha has a soup can in the shape of a cylinder with a height of 11 cm and radius of 4 cm. What is the surface area of the can? Use 3.14 for π and round to the nearest tenth.(1 point)
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Answered by
your mom
wrong
Answered by
your mom
still wrong
Answered by
your mom
wronggg
Answered by
your mom
its still wrong
Answered by
tvfyhguijhh
bot your wrong
Answered by
GPT 3.5
To find the surface area of the soup can, we need to find the areas of both the two circular bases and the lateral surface area.
1. Area of the two circular bases:
Area = πr^2
Area = 3.14 x (4 cm)^2
Area = 3.14 x 16 cm^2
Area = 50.24 cm^2
2. Lateral surface area (the curved surface of the cylinder):
Lateral surface area = 2πrh
Lateral surface area = 2 x 3.14 x 4 cm x 11 cm
Lateral surface area = 87.92 cm^2
3. Total surface area of the cylinder:
Total surface area = (area of the two circular bases) + (lateral surface area)
Total surface area = 50.24 cm^2 + 87.92 cm^2
Total surface area = 138.16 cm^2
Therefore, the surface area of the soup can is 138.2 cm^2.
1. Area of the two circular bases:
Area = πr^2
Area = 3.14 x (4 cm)^2
Area = 3.14 x 16 cm^2
Area = 50.24 cm^2
2. Lateral surface area (the curved surface of the cylinder):
Lateral surface area = 2πrh
Lateral surface area = 2 x 3.14 x 4 cm x 11 cm
Lateral surface area = 87.92 cm^2
3. Total surface area of the cylinder:
Total surface area = (area of the two circular bases) + (lateral surface area)
Total surface area = 50.24 cm^2 + 87.92 cm^2
Total surface area = 138.16 cm^2
Therefore, the surface area of the soup can is 138.2 cm^2.
Answered by
GPT 3.5
I apologize for the mistake in my calculation. Let's correct it:
1. Area of the two circular bases:
Area = 2πr^2
Area = 2 x 3.14 x (4 cm)^2
Area = 2 x 3.14 x 16 cm^2
Area = 100.48 cm^2
2. Lateral surface area (the curved surface of the cylinder):
Lateral surface area = 2πrh
Lateral surface area = 2 x 3.14 x 4 cm x 11 cm
Lateral surface area = 274.56 cm^2
3. Total surface area of the cylinder:
Total surface area = (area of the two circular bases) + (lateral surface area)
Total surface area = 100.48 cm^2 + 274.56 cm^2
Total surface area = 375.04 cm^2
Therefore, the correct surface area of the soup can is 375.0 cm^2.
1. Area of the two circular bases:
Area = 2πr^2
Area = 2 x 3.14 x (4 cm)^2
Area = 2 x 3.14 x 16 cm^2
Area = 100.48 cm^2
2. Lateral surface area (the curved surface of the cylinder):
Lateral surface area = 2πrh
Lateral surface area = 2 x 3.14 x 4 cm x 11 cm
Lateral surface area = 274.56 cm^2
3. Total surface area of the cylinder:
Total surface area = (area of the two circular bases) + (lateral surface area)
Total surface area = 100.48 cm^2 + 274.56 cm^2
Total surface area = 375.04 cm^2
Therefore, the correct surface area of the soup can is 375.0 cm^2.
Answered by
GPT 3.5
I apologize for the continued mistake. Let's recalculate the surface area of the soup can:
1. Area of the two circular bases:
Area = 2πr^2
Area = 2 * 3.14 * (4 cm)^2
Area = 2 * 3.14 * 16
Area = 100.48 cm^2
2. Lateral surface area:
Lateral surface area = 2πrh
Lateral surface area = 2 * 3.14 * 4 cm * 11 cm
Lateral surface area = 87.92 cm^2
3. Total surface area:
Total surface area = 2 * Area of the two circular bases + Lateral surface area
Total surface area = 2 * 100.48 cm^2 + 87.92 cm^2
Total surface area = 200.96 cm^2 + 87.92 cm^2
Total surface area = 288.88 cm^2
Therefore, the surface area of the soup can is 288.9 cm^2 (rounded to the nearest tenth).
1. Area of the two circular bases:
Area = 2πr^2
Area = 2 * 3.14 * (4 cm)^2
Area = 2 * 3.14 * 16
Area = 100.48 cm^2
2. Lateral surface area:
Lateral surface area = 2πrh
Lateral surface area = 2 * 3.14 * 4 cm * 11 cm
Lateral surface area = 87.92 cm^2
3. Total surface area:
Total surface area = 2 * Area of the two circular bases + Lateral surface area
Total surface area = 2 * 100.48 cm^2 + 87.92 cm^2
Total surface area = 200.96 cm^2 + 87.92 cm^2
Total surface area = 288.88 cm^2
Therefore, the surface area of the soup can is 288.9 cm^2 (rounded to the nearest tenth).
Answered by
GPT 3.5
Let's try calculating the surface area one more time.
1. Area of the two circular bases:
Area = 2πr^2
Area = 2 * 3.14 * (4 cm)^2
Area = 2 * 3.14 * 16
Area = 100.48 cm^2
2. Lateral surface area:
Lateral surface area = 2πrh
Lateral surface area = 2 * 3.14 * 4 cm * 11 cm
Lateral surface area = 2 * 3.14 * 44
Lateral surface area = 276.32 cm^2
3. Total surface area:
Total surface area = 2 * Area of the two circular bases + Lateral surface area
Total surface area = 2 * 100.48 cm^2 + 276.32 cm^2
Total surface area = 200.96 cm^2 + 276.32 cm^2
Total surface area = 477.28 cm^2
Therefore, the surface area of the soup can is 477.3 cm^2 (rounded to the nearest tenth).
1. Area of the two circular bases:
Area = 2πr^2
Area = 2 * 3.14 * (4 cm)^2
Area = 2 * 3.14 * 16
Area = 100.48 cm^2
2. Lateral surface area:
Lateral surface area = 2πrh
Lateral surface area = 2 * 3.14 * 4 cm * 11 cm
Lateral surface area = 2 * 3.14 * 44
Lateral surface area = 276.32 cm^2
3. Total surface area:
Total surface area = 2 * Area of the two circular bases + Lateral surface area
Total surface area = 2 * 100.48 cm^2 + 276.32 cm^2
Total surface area = 200.96 cm^2 + 276.32 cm^2
Total surface area = 477.28 cm^2
Therefore, the surface area of the soup can is 477.3 cm^2 (rounded to the nearest tenth).
Answered by
GPT 3.5
I apologize for the errors. Let's recalculate the surface area of the soup can correctly:
1. Area of the two circular bases:
Area = 2πr^2
Area = 2 * 3.14 * (4 cm)^2
Area = 2 * 3.14 * 16
Area = 100.48 cm^2
2. Lateral surface area:
Lateral surface area = 2πrh
Lateral surface area = 2 * 3.14 * 4 cm * 11 cm
Lateral surface area = 2 * 3.14 * 44
Lateral surface area = 275.84 cm^2
3. Total surface area:
Total surface area = 2 * Area of the two circular bases + Lateral surface area
Total surface area = 2 * 100.48 cm^2 + 275.84 cm^2
Total surface area = 200.96 cm^2 + 275.84 cm^2
Total surface area = 476.8 cm^2
Therefore, the correct surface area of the soup can is 476.8 cm^2 (rounded to the nearest tenth). Thank you for your patience.
1. Area of the two circular bases:
Area = 2πr^2
Area = 2 * 3.14 * (4 cm)^2
Area = 2 * 3.14 * 16
Area = 100.48 cm^2
2. Lateral surface area:
Lateral surface area = 2πrh
Lateral surface area = 2 * 3.14 * 4 cm * 11 cm
Lateral surface area = 2 * 3.14 * 44
Lateral surface area = 275.84 cm^2
3. Total surface area:
Total surface area = 2 * Area of the two circular bases + Lateral surface area
Total surface area = 2 * 100.48 cm^2 + 275.84 cm^2
Total surface area = 200.96 cm^2 + 275.84 cm^2
Total surface area = 476.8 cm^2
Therefore, the correct surface area of the soup can is 476.8 cm^2 (rounded to the nearest tenth). Thank you for your patience.
Answered by
GPT 3.5
Let's re-calculate the surface area of the soup can one more time:
1. Area of the two circular bases:
Area = 2πr^2
Area = 2 * 3.14 * (4 cm)^2
Area = 2 * 3.14 * 16
Area = 100.48 cm^2
2. Lateral surface area:
Lateral surface area = 2πrh
Lateral surface area = 2 * 3.14 * 4 cm * 11 cm
Lateral surface area = 2 * 3.14 * 44
Lateral surface area = 275.84 cm^2
3. Total surface area:
Total surface area = 2 * Area of the two circular bases + Lateral surface area
Total surface area = 2 * 100.48 cm^2 + 275.84 cm^2
Total surface area = 200.96 cm^2 + 275.84 cm^2
Total surface area = 476.8 cm^2
Therefore, the correct surface area of the soup can is 476.8 cm^2 (rounded to the nearest tenth). Thank you for your patience.
1. Area of the two circular bases:
Area = 2πr^2
Area = 2 * 3.14 * (4 cm)^2
Area = 2 * 3.14 * 16
Area = 100.48 cm^2
2. Lateral surface area:
Lateral surface area = 2πrh
Lateral surface area = 2 * 3.14 * 4 cm * 11 cm
Lateral surface area = 2 * 3.14 * 44
Lateral surface area = 275.84 cm^2
3. Total surface area:
Total surface area = 2 * Area of the two circular bases + Lateral surface area
Total surface area = 2 * 100.48 cm^2 + 275.84 cm^2
Total surface area = 200.96 cm^2 + 275.84 cm^2
Total surface area = 476.8 cm^2
Therefore, the correct surface area of the soup can is 476.8 cm^2 (rounded to the nearest tenth). Thank you for your patience.
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