Asked by isabela
Martha's $18,750 is invested in two accounts, one earning 12% interest and the other earning 10%. After 1 year, her combined interest income is $2,117. How much has she invested at each rate?
Answers
Answered by
bobpursley
let $ be the amount at 12 percent
$*0.12+ (18750-$)*0.10=2117
solve for $
$*.02=2117-1875
$=12,100 check that, so then the other is 18750-12,100=6,650
$*0.12+ (18750-$)*0.10=2117
solve for $
$*.02=2117-1875
$=12,100 check that, so then the other is 18750-12,100=6,650
Answered by
Steve
If x is invested at 12%, then the rest (18750-x) is at 10%
So, just add up the interest:
0.12x + 0.10(18750-x) = 2117
So, just add up the interest:
0.12x + 0.10(18750-x) = 2117
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