Asked by Calculus

can someone please explain

h t t p : / / w w w . j i s k h a . c o m / d i s p l a y . c g i ? i d = 1 2 5 7 0 4 1 1 4 5

Answers

Answered by bobpursley
division by zero is NOT allowed
(x+5)/(x-3) is valid for all x except x=3

Answered by READ
but I can evalute using limits...
Answered by CAN SOMEONE READ THIS
please
Answered by drwls
Whatever you did using limits is wrong.
Answered by MathMate
The limit at x=3 exists if lim x→3- equals lim x→3+.

In this case, the two are not equal, because they tend toward inifinity in opposite directions, so the limit does NOT exist. Even if they tend toward infinity in the same direction, the limit does not exist.

Even in the case where the limit exists, as in the case of
f(x)=(x-3)*(x+5)/(x-3),
the point x=3 remains a hole in the domain of f(x).

In the case of f(x)=(x+5)/(x-3), there is no doubt that the point x=3 is excluded from the domain, which is ℝ\3.

There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions