Asked by Calculus
can someone please explain
h t t p : / / w w w . j i s k h a . c o m / d i s p l a y . c g i ? i d = 1 2 5 7 0 4 1 1 4 5
h t t p : / / w w w . j i s k h a . c o m / d i s p l a y . c g i ? i d = 1 2 5 7 0 4 1 1 4 5
Answers
Answered by
bobpursley
division by zero is NOT allowed
(x+5)/(x-3) is valid for all x except x=3
(x+5)/(x-3) is valid for all x except x=3
Answered by
READ
but I can evalute using limits...
Answered by
CAN SOMEONE READ THIS
please
Answered by
drwls
Whatever you did using limits is wrong.
Answered by
MathMate
The limit at x=3 exists if lim x→3- equals lim x→3+.
In this case, the two are not equal, because they tend toward inifinity in opposite directions, so the limit does NOT exist. Even if they tend toward infinity in the same direction, the limit does not exist.
Even in the case where the limit exists, as in the case of
f(x)=(x-3)*(x+5)/(x-3),
the point x=3 remains a hole in the domain of f(x).
In the case of f(x)=(x+5)/(x-3), there is no doubt that the point x=3 is excluded from the domain, which is ℝ\3.
In this case, the two are not equal, because they tend toward inifinity in opposite directions, so the limit does NOT exist. Even if they tend toward infinity in the same direction, the limit does not exist.
Even in the case where the limit exists, as in the case of
f(x)=(x-3)*(x+5)/(x-3),
the point x=3 remains a hole in the domain of f(x).
In the case of f(x)=(x+5)/(x-3), there is no doubt that the point x=3 is excluded from the domain, which is ℝ\3.
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