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When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV^{1....Asked by Ash
When air expands adiabatically (without gaining or losing heat), its pressure and volume are related by the equation PV^1,4=C where C is a constant. Suppose that a a certain instant the volume is 520 cubic centimeters and the pressure is 99kPa and is decreasing at a rate of 11 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant?
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Answered by
bobpursley
PV^1.4=C
V^1.4 dp/dt+ 1.4pV^.4 dv/dt=0
So you are given, V, P, dp/dt, solve for dv/dt
V^1.4 dp/dt+ 1.4pV^.4 dv/dt=0
So you are given, V, P, dp/dt, solve for dv/dt
Answered by
Anonymous
noob
Answered by
Anonymous
uibvguo
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