Asked by Mark
A GAS EXPANDS IN VOLUME FROM 26.7 ML TO 89.3 ML AT CONSTANTTEMPERATURE. CALCULATE THE WORK DONE (IN JOULES) IF THE GASEXPANDS (A) AGAINST A VACUUM,(B) AGAINST A CONSTANT PRESSUREOF 1.5 ATM, AND (C) AGAINST A CONSTANT PRESSURE OF 2.8 ATM.
Answers
Answered by
Ms. Sue
I'm sorry you don't know what a school subject is.
Answered by
DrBob222
A.
Expansion work (or PV work) is
work = -p(v final-v initial)
If p is zero, the PV work must be zero since any number x zero is zero.
B. Substitute the numbers into -p(v final - v initial). p is 1.5 for B and 2.8 for C.
Delta V is 89.3 - 26.7 = ? mL and change that to L.
Work has units of L*atm. Change to joules by L*atm x 101.325 J/atm = ? J
Expansion work (or PV work) is
work = -p(v final-v initial)
If p is zero, the PV work must be zero since any number x zero is zero.
B. Substitute the numbers into -p(v final - v initial). p is 1.5 for B and 2.8 for C.
Delta V is 89.3 - 26.7 = ? mL and change that to L.
Work has units of L*atm. Change to joules by L*atm x 101.325 J/atm = ? J
Answered by
Emmanuel Kamara
A certain gas expand in volume from 2.0L to 6.0L at constant temperature. Calculate the work done by the gas if it expands (1)against a vaccum and( 2) against pressure of 1.2 atm
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