sin theta/2cos theta/2=1/2 sine theta show the identiy and work

1-2sin^2(theta/2)=2cos^2(theta/2)-1

Solve: 2cos^2 theta - 3cos theta+ 1= 0 interval [0, 2ð)

cos theta= .5 2cos theta= .5 how do you do this?

if sine theta=.3416 and theta is in quadrant I what is cos theta/2? Using double angle identities.

2cos^2 theta + 5 sin theta - 4 = 0

2cos^2(theta) + Sin(theta)=1 I know I have to use the quadratic formula but i'm having trouble a...

2cos^2 theta/3-1

sine theta = 1/3 and cos theta = 2/3, find tan theta

solve the equation (2cos theta +1)(tan theta minus 1)=0 for all values between 0 and 2pii.

Cos(theta)sin(theta)-2cos(theta)=0

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