Asked by Nikita
A satellite orbits at an average altitude of h = 409 km. What is its orbital speed? Use REarth = 6370 km and
mEarth = 5.98 x 10^24 kg
mEarth = 5.98 x 10^24 kg
Answers
Answered by
bobpursley
set centripetal force = gravitational force
GMm/(r+h)^2=mv^2/(r+h)
v= 2PI (r+h)/24hrsinSeconds
change all kilometers to meters. Watch units.
GMm/(r+h)^2=mv^2/(r+h)
v= 2PI (r+h)/24hrsinSeconds
change all kilometers to meters. Watch units.
Answered by
randy
can you please explain the v=...part i don't understand what you mean by 24hrsinseconds?
Answered by
Anonymous
is GMm gravity (9.81) multiplied by the mEarth?
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