Asked by Alex
A 71.4 kg satellite orbits the earth at a distance of 7.00E6 m from the center of the earth (a distance of 630 km above the earth's surface). How fast must the satellite be going to maintain its orbit if the free fall acceleration at this distance is 8.14 m/s^2?
Answers
Answered by
bobpursley
8.14=v^2/r where r= 7e6 m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.