Ask a New Question

Ok so I have to find a vertical asymptote with denominator 3x^3-x-1. So then the denominator must not equal zero. But i just can't solve the cubic function i tried long division! but it didn't work

2 answers

I would graph it and find the roots.

We aren't allowed graphing calculators, plus it a rational function

Similar Questions

Why is there no vertical asymptote onF(x) = x/(x^2+1) What i learned is that to find vertical asymptote you have to set the
1. 4 answers
State the equation of a rational function in the form f(x)=(ax+b)/(cx+d), if the vertical asymptote is x=3/5, the horizontal
1. 2 answers
I'm working on vertical asymptotes when factoring 6x^2 - 6 (denominator). I came up with 6(x^2-1). Then I was trying to find the
1. 1 answer
A rational function f(x) contains quadratic functions in both the numerator and denominator. Also the function f(x) has a
1. 1 answer

more similar questions