Asked by emma
How do you find the vertical asymptote of f(x) = -ln(1-x)
Answers
Answered by
R_scott
logs are not defined for negative arguments
as x approaches one (from the negative direction)
... f(x) approaches infinity
x = 1 is the asymptote
as x approaches one (from the negative direction)
... f(x) approaches infinity
x = 1 is the asymptote
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