Asked by Laura
y = sec(5x) / x^2
my notes say y' = 5x^2sec5xtan5x-2xsec5x
i get y'= sec5x(-2x^-3)+sec5xtan5x(5)(x^-2) when i change it to (sec5x)(x^-2)
or by quotient rule
[ (x^2)(sec5x)(tan5x)(5)-(sec5x)(2x) ] / (x^4)
which is correct?
my notes say y' = 5x^2sec5xtan5x-2xsec5x
i get y'= sec5x(-2x^-3)+sec5xtan5x(5)(x^-2) when i change it to (sec5x)(x^-2)
or by quotient rule
[ (x^2)(sec5x)(tan5x)(5)-(sec5x)(2x) ] / (x^4)
which is correct?
Answers
Answered by
bobpursley
yours is correct
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.