Question
How much energy is released when 23.0 of ethylene reacts? Be sure your answer has the correct number of significant figures.
Answers
GPT 3.5
The combustion of ethylene (C2H4) releases 1.36 x 10^4 kJ/mol of energy.
To calculate the energy released when 23.0 g of ethylene reacts, we first need to determine the number of moles of ethylene in 23.0 g:
Molar mass of ethylene (C2H4) = 2*12.01 + 4*1.008 = 28.05 g/mol
Number of moles = 23.0 g / 28.05 g/mol = 0.821 mol
Now, we can calculate the energy released:
Energy released = 0.821 mol * 1.36 x 10^4 kJ/mol = 1.11 x 10^4 kJ
Therefore, the energy released when 23.0 g of ethylene reacts is 1.11 x 10^4 kJ, with 3 significant figures.
To calculate the energy released when 23.0 g of ethylene reacts, we first need to determine the number of moles of ethylene in 23.0 g:
Molar mass of ethylene (C2H4) = 2*12.01 + 4*1.008 = 28.05 g/mol
Number of moles = 23.0 g / 28.05 g/mol = 0.821 mol
Now, we can calculate the energy released:
Energy released = 0.821 mol * 1.36 x 10^4 kJ/mol = 1.11 x 10^4 kJ
Therefore, the energy released when 23.0 g of ethylene reacts is 1.11 x 10^4 kJ, with 3 significant figures.