3(4x+8x)=3x+6

Question

7x+3=7x+3

Plug more than one point into the original equations and check to show that the equations can have more that one solution. explain your work

Answer 1

Let's plug in x=0 into the first equation:

3(4(0)+8(0))=3(0)+6
3(0)=0+6
0=6

This equation is false when x=0, which means that x=0 is not a solution to the first equation.

Now let's plug in x=1 into the first equation:

3(4(1)+8(1))=3(1)+6
3(4+8)=3+6
3(12)=9
36=9

This equation is also false when x=1, which means that x=1 is not a solution to the first equation.

Now let's plug in x=0 into the second equation:

7(0)+3=7(0)+3
0+3=0+3
3=3

This equation is true when x=0, which means that x=0 is a solution to the second equation.

Now let's plug in x=1 into the second equation:

7(1)+3=7(1)+3
7+3=7+3
10=10

This equation is also true when x=1, which means that x=1 is a solution to the second equation.

Therefore, by plugging in x=0 and x=1 into the original equations, we can see that the equations have more than one solution.

Answer 2

can you shorten that

Answer 3

By plugging in x=0 and x=1 into the original equations, we can see that the equations have more than one solution. The first equation does not hold true for x=0 or x=1, while the second equation holds true for both x=0 and x=1. This shows that the equations can have multiple solutions.