Let's plug in two different values for x into the first equation and two different values for x into the second equation and see if they hold true.
For the first equation 7x + 3 = 7x + 3:
Let's plug in x = 1:
7(1) + 3 = 7(1) + 3
10 = 10 (True)
Now, let's plug in x = 2:
7(2) + 3 = 7(2) + 3
17 = 17 (True)
Since both values of x satisfy the equation, there are multiple solutions to this equation.
For the second equation 3(4x + 8) = 4(3x + 6):
Let's plug in x = 1:
3(4(1) + 8) = 4(3(1) + 6)
3(12) = 4(9)
36 = 36 (True)
Now, let's plug in x = 2:
3(4(2) + 8) = 4(3(2) + 6)
3(16) = 4(12)
48 = 48 (True)
Similarly, both values of x satisfy the second equation, indicating that there are multiple solutions.
In conclusion, by plugging in different values for x into both equations and checking if the equations hold true, we have shown that both equations can have more than one solution.
Plug more than one point into the original equations and check to show that the
equations can have more than one solution. Explain your work. 7x+3=7x+3 and 3(4x+8)=4(3x+6)
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