which statement is true

is 6^18/6^5 less than greater than or equal to (6^4)^2

11 answers

6^18/6^5 is equal to 6^(18-5) which simplifies to 6^13.

(6^4)^2 is equal to 6^(4*2) which simplifies to 6^8.

6^13 is greater than 6^8, so the statement 6^18/6^5 is greater than (6^4)^2 is true.
in triangle MNP, what is sinM?
To find the sine of angle M in triangle MNP, we need to use the formula for sine in a right triangle.

sinM = Opposite / Hypotenuse

However, in order to calculate the sine of angle M, we need more information about the triangle MNP, such as the lengths of sides MP, NP, and MN or the measure of angle M itself. Without this information, we cannot determine the sine of angle M in triangle MNP.
what is the area of a triangle with abase of 32 yards and a height of 17 yards?

49 yd^2
136 yd^2
544 yd^2
272 yd^2
The formula for the area of a triangle is:
Area = 0.5 * base * height

Given that the base is 32 yards and the height is 17 yards, we can substitute these values into the formula:
Area = 0.5 * 32 * 17
Area = 0.5 * 544
Area = 272 square yards

Therefore, the area of the triangle with a base of 32 yards and a height of 17 yards is 272 square yards.

So, the correct answer is 272 yd^2.
the first four terms of an arithmetic sequence are -11, -5, 1, 7. what is the equation for an
To find the equation for an arithmetic sequence, we need to determine the common difference (d) between consecutive terms.

From the given sequence -11, -5, 1, 7, we can see that the common difference is 6 (each term is 6 greater than the previous one).

The general equation for the nth term (a_n) of an arithmetic sequence is:
a_n = a_1 + (n - 1)d

where:
- a_n is the nth term
- a_1 is the first term
- d is the common difference between terms
- n is the term number

In this case, the first term (a_1) is -11 and the common difference (d) is 6. Therefore, the equation for the arithmetic sequence is:
a_n = -11 + (n - 1)6

Simplifying it, we get:
a_n = -11 + 6n - 6
a_n = 6n - 17

Thus, the equation for the arithmetic sequence is a_n = 6n - 17.
what is the LCM of 30 and 45?
To find the Least Common Multiple (LCM) of 30 and 45, we need to find the smallest common multiple that is divisible by both 30 and 45.

We can start by finding the prime factors of each number:
30 = 2 * 3 * 5
45 = 3 * 3 * 5

The LCM is the product of all prime factors with the highest power that appears in either factorization:
LCM = 2 * 3 * 3 * 5 = 90

Therefore, the LCM of 30 and 45 is 90.
(16)^1/2 = ?
To calculate (16)^(1/2), which is the square root of 16, you will get:

(16)^(1/2) = √16 = 4

Therefore, the square root of 16 is 4.
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