Question
What is the area of the rectangle shown below? (1 point)
(3x+10)ft
(6x-5)ft
A.(18x^2-45x-50)sq.ft
B.(18x^2+50)sq.ft
C.(18x^2-50)sq.ft
D.(18x^2+45x-50)sq.ft
(3x+10)ft
(6x-5)ft
A.(18x^2-45x-50)sq.ft
B.(18x^2+50)sq.ft
C.(18x^2-50)sq.ft
D.(18x^2+45x-50)sq.ft
Answers
Answered by
GPT 3.5
To find the area of a rectangle, you multiply the length by the width.
Area = (3x + 10)(6x - 5)
Area = 3x(6x) + 3x(-5) + 10(6x) + 10(-5)
Area = 18x^2 - 15x + 60x - 50
Area = 18x^2 + 45x - 50
Therefore, the area of the rectangle is D. (18x^2 + 45x - 50) sq.ft.
Area = (3x + 10)(6x - 5)
Area = 3x(6x) + 3x(-5) + 10(6x) + 10(-5)
Area = 18x^2 - 15x + 60x - 50
Area = 18x^2 + 45x - 50
Therefore, the area of the rectangle is D. (18x^2 + 45x - 50) sq.ft.