Question
What is the area of the rectangle width 1 1/5 m length 2 2/3 m 0/0 square meters
Answers
Answered by
GPT-4o mini
To find the area of a rectangle, you multiply its width by its length.
First, let's convert the mixed numbers to improper fractions:
1. **Width**: \( 1 \frac{1}{5} = \frac{5}{5} + \frac{1}{5} = \frac{6}{5} \) m
2. **Length**: \( 2 \frac{2}{3} = \frac{6}{3} + \frac{2}{3} = \frac{8}{3} \) m
Now, calculate the area \( A \):
\[
A = \text{Width} \times \text{Length} = \frac{6}{5} \times \frac{8}{3}
\]
Multiply the numerators and the denominators:
\[
A = \frac{6 \times 8}{5 \times 3} = \frac{48}{15}
\]
Now, simplify \( \frac{48}{15} \):
\[
\frac{48}{15} = \frac{16}{5} \text{ m}^2 \quad (\text{dividing numerator and denominator by 3})
\]
Now, converting \( \frac{16}{5} \) to a mixed number, we get:
\[
\frac{16}{5} = 3 \frac{1}{5} \text{ m}^2
\]
Therefore, the area of the rectangle is \( \frac{16}{5} \text{ m}^2 \) or approximately \( 3.2 \text{ m}^2 \).
First, let's convert the mixed numbers to improper fractions:
1. **Width**: \( 1 \frac{1}{5} = \frac{5}{5} + \frac{1}{5} = \frac{6}{5} \) m
2. **Length**: \( 2 \frac{2}{3} = \frac{6}{3} + \frac{2}{3} = \frac{8}{3} \) m
Now, calculate the area \( A \):
\[
A = \text{Width} \times \text{Length} = \frac{6}{5} \times \frac{8}{3}
\]
Multiply the numerators and the denominators:
\[
A = \frac{6 \times 8}{5 \times 3} = \frac{48}{15}
\]
Now, simplify \( \frac{48}{15} \):
\[
\frac{48}{15} = \frac{16}{5} \text{ m}^2 \quad (\text{dividing numerator and denominator by 3})
\]
Now, converting \( \frac{16}{5} \) to a mixed number, we get:
\[
\frac{16}{5} = 3 \frac{1}{5} \text{ m}^2
\]
Therefore, the area of the rectangle is \( \frac{16}{5} \text{ m}^2 \) or approximately \( 3.2 \text{ m}^2 \).