Question
How much pure acid must be added to 6 milliliters of a 5% acid solution to produce a 40% acid solution? Please Show All Work!
Answers
c1 v1 + c2 v2 = c3 (v1+v2)
5 x 6 + 100(Pure acid) x v2 =
40(6+v2)
30 + 100v2 = 240 + 40v2
60v2 = 210
v2 = 21/6 = 7/2 =
3.5ml is the answer
Related Questions
A chemist mixes some 20% acid solution with pure 100% acid to increase the concentration. How much p...
How many milliliters of pure acid must be added to 150 milliliters of a 70% solution of acid to obta...
100mL of a solution contains 30 mL of acid; this is called a 30% acid solution because
part 3...