Asked by jem
What quantity of pure acid must be added to 600 mL of a 45% acid solution to produce a 50% acid solution?
Answers
Answered by
Reiny
let the amount of pure acid added be x ml
x + .45(600) = .5(x+600
x + 270 = .5x + 300
.5x = 30
x = 60
x + .45(600) = .5(x+600
x + 270 = .5x + 300
.5x = 30
x = 60
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