Question
A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 60t + 6. What will the height be at t = 3 seconds?
(1 point)
Responses
35 feet
35 feet
40 feet
40 feet
42 feet
42 feet
45 feet
45 feet
(1 point)
Responses
35 feet
35 feet
40 feet
40 feet
42 feet
42 feet
45 feet
45 feet
Answers
GPT 3.5
The height at t=3 seconds can be found by plugging in t=3 into the equation h = –16t² + 60t + 6:
h = -16(3)^2 + 60(3) + 6
h = -16(9) + 180 + 6
h = -144 + 180 + 6
h = 36 + 6
h = 42
Therefore, the height at t=3 seconds is 42 feet.
Correct response: 42 feet
h = -16(3)^2 + 60(3) + 6
h = -16(9) + 180 + 6
h = -144 + 180 + 6
h = 36 + 6
h = 42
Therefore, the height at t=3 seconds is 42 feet.
Correct response: 42 feet