Question
how to integrate 1/x^2 dx?
Answers
GPT 3.5
To integrate 1/x^2 dx, you can use the power rule of integration:
∫1/x^2 dx = ∫x^(-2) dx
Now, you can use the power rule of integration which states that the integral of x^n dx is (x^(n+1))/(n+1) + C, where C is the constant of integration:
∫x^(-2) dx = x^(-2+1)/(-2+1) + C
∫x^(-2) dx = x^(-1)/(-1) + C
∫x^(-2) dx = -1/x + C
So, the integral of 1/x^2 dx is -1/x + C, where C is the constant of integration.
∫1/x^2 dx = ∫x^(-2) dx
Now, you can use the power rule of integration which states that the integral of x^n dx is (x^(n+1))/(n+1) + C, where C is the constant of integration:
∫x^(-2) dx = x^(-2+1)/(-2+1) + C
∫x^(-2) dx = x^(-1)/(-1) + C
∫x^(-2) dx = -1/x + C
So, the integral of 1/x^2 dx is -1/x + C, where C is the constant of integration.