We can simplify the given expression first:
t√t + √t = t^(3/2) + t^(1/2)
Now, we can integrate each term separately:
∫t^(3/2) dt = (2/5)t^(5/2) + C1
∫t^(1/2) dt = (2/3)t^(3/2) + C2
Therefore, the integral of the given expression (t√t + √t) dt is:
(2/5)t^(5/2) + (2/3)t^(3/2) + C
where C is the constant of integration.
(t√t+√t) dt integrate
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