Asked by Nancy
How does the drag force on an object change if the object's area is halved while the wind speed is doubled, while keeping everything else the same?
i think it would double if you use this eqn:
f= 1/4 A v^2
can someone verify if this eqn is correct to use in this problem?
i think it would double if you use this eqn:
f= 1/4 A v^2
can someone verify if this eqn is correct to use in this problem?
Answers
Answered by
tchrwill
The drag force on an object is defined by D1 = Cd(µ/2)A(V^2) where Cd is the drag coeficient of the object, µ is the density of the atmosphere, A is the frontal area of the object and V is the velocity of the object.
Doubling the speed and halving the area results in D2 = 2^2(1/2)D1 = 2D1
Doubling the speed and halving the area results in D2 = 2^2(1/2)D1 = 2D1
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