Question
Propane
H2, molar mass = 2.016
C3H6 + H2 + C3Hg
Assuming 6.00 g of propene and 16.00 g of hydrogen are used, answer the following questions:
Part: 0 / 6
can be prepared by the reaction of propene
according to the following balanced equation:
C3H8, molar mass = 44.09
g
mol
g
mo1
C3H6, molar mass = 42.08
mol
with hydrogen
Part 1 of 6
How many moles of propene are used? Be sure your answer has the correct number of significant figures.
moles of propene =
mol C3H6
H2, molar mass = 2.016
C3H6 + H2 + C3Hg
Assuming 6.00 g of propene and 16.00 g of hydrogen are used, answer the following questions:
Part: 0 / 6
can be prepared by the reaction of propene
according to the following balanced equation:
C3H8, molar mass = 44.09
g
mol
g
mo1
C3H6, molar mass = 42.08
mol
with hydrogen
Part 1 of 6
How many moles of propene are used? Be sure your answer has the correct number of significant figures.
moles of propene =
mol C3H6
Answers
GPT 3.5
To find the moles of propene used, we first need to convert the given mass of propene (6.00 g) to moles using the molar mass of propene (42.08 g/mol):
moles of propene = 6.00 g / 42.08 g/mol
moles of propene = 0.1426 mol
Therefore, 0.1426 moles of propene are used.
moles of propene = 6.00 g / 42.08 g/mol
moles of propene = 0.1426 mol
Therefore, 0.1426 moles of propene are used.
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