Propane

H2, molar mass = 2.016

C3H6 + H2 + C3Hg

Assuming 6.00 g of propene and 16.00 g of hydrogen are used, answer the following questions:

Part: 0 / 6

can be prepared by the reaction of propene

according to the following balanced equation:

C3H8, molar mass = 44.09

g
mol

g

mo1

C3H6, molar mass = 42.08

mol

with hydrogen

Part 2 of 6
moles of hydrogen =

Part 2 of 6

How many moles of hydrogen are used? Be sure your answer has the correct number of significant figures.

mol H2

1 answer

To find the moles of hydrogen used, we first need to convert the given mass of hydrogen (16.00 g) to moles.

Molar mass of H2 = 2.016 g/mol

Moles of H2 = 16.00 g / 2.016 g/mol = 7.9375 mol

Therefore, the moles of hydrogen used are 7.94 mol.