Question

SPH3U1

Two blocks of mass 500.0 g and 200.0 g are suspended vertically as shown in the diagram. The top string is lifted vertically upwards with a force of 8.48N on the 500.0 g Block

(sorry no diagram)

Thank you very much for your help
What is the question? Acceleration? Tension in the lower string?
If acceleration = a,
then
(M+m)(g+a) = F = 8.48N
Solve for a.
Tension in the lower string = T
= m(g+a)
Wow thank you very much!!!!
You're welcome.

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