Question
Two blocks of mass m1 = 320 g and m2 = 725 g are pushed by a force. The coefficient of kinetic friction between each block and the ground is 0.4. The blocks move together (with one pushing the other) with an acceleration of 225 cm/s2. What is the value of the applied force in Newtons?
Answers
Henry
M*g = (0.320+0.725) * 9.8 = 10.24 N.
Fk = u*Fn = (0.4+0.4)10.24 = 8.19 N. = Force of kinetic friction.
Fap-Fk = M*a.
Fap-8.19 = ((0.320+0.725)*2.25
Fap = ?.
Fk = u*Fn = (0.4+0.4)10.24 = 8.19 N. = Force of kinetic friction.
Fap-Fk = M*a.
Fap-8.19 = ((0.320+0.725)*2.25
Fap = ?.